A shop sells pairs of trainers for £68 each. They make a percentage profit of 70% on each pair.
1 answer:
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Answer:
$59.96
Step-by-step explanation:
Given:
The science club has raised $154. 24 to buy food for a polar bear cub at the zoo.
It costs $53.55 to feed the cub each week.
Question asked:
How much more money does the club need to raise to feed the cub for one month (four weeks)?
Solution:
Cost of feed for the cub for 1 week = $53.55
Cost of feed for the cub for 4 weeks = $53.55 4 = $214.20
Money raised by the science club = $154. 24
More money needed by science club = Cost of feed for 4 weeks - Money raised by the science club
More money needed by science club = $214.20 - $154. 24
= $59.96
Thus, the science club will be needed $59.96 more money for one month (four weeks) feed.
Answer:
Parallel
Step-by-step explanation:
Parallel lines are 2 coplanar lines that dont intersect at any point
Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) =
In order to maximize the revenue, set
.............(i)
.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴
So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94