Let x and y represent angles 1 and 2, respectively. The given relations tell you
... x + y = 180 . . . . the sum of measures of a linear pair is 180°
... y = 2x + 6 . . . . angle 2 is 6 more than twice angle 1
One way to solve these is to add twice the first equation to the second.
... 2(x + y) + (y) = 2(180) + (2x +6)
Now, subtract 2x
... 3y = 366
... y = 122 . . . . divide by the coefficient of y
The measure of angle 2 is 122°.
Answer:
21
Step-by-step explanation:
Answer:
15.1
Step-by-step explanation:
29.34
-14.24
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15.10
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
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1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
To find a percentage, you the decimal point in the percent two places to the right 16% = 0.16. Then multiply.
0.16 • 400 = 64
16% of 400 = 64
