Answer:
Check Explanation.
Explanation:
For a simple pendulum, the period is given as
T = 2π√(L/g)
It is also given as
T = 2π√(m/k)
where
T = period of oscillation
m = mass of the pendulum
L = length
g = acceleration due to gravity
k = force constant
Equating this two equations,
2π√(L/g) = 2π√(m/k)
(L/g) = (m/k)
(m/L) = (k/g)
So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.
Hope this Helps!!!
Angular acceleration is simply the ratio of the Torque
over the rotation inertia, that is:
Angular acceleration = Torque / Rotational inertia
So substituting the values:
Angular acceleration = 2.4 N m / 4.0 kg m2
<span>Angular acceleration = 0.7 rad/s^2</span>
Democritus was the first contributor to the atomic theory
When its tangential speed is constant
<span>Although the speed of an object that has a uniform circular motion is constant, its velocity is </span>not constant<span>. Not only that, but it is actually changing constantly.</span><span>
</span>
The law of conservation of momentum tells us that momentum
is conserved, therefore total initial momentum should be equal to total final
momentum. In this case, we can expressed this mathematically as:
mA vA + mB vB = m v
where, m is the mass in kg, v is the velocity in m/s
since m is the total mass, m = mA + mB, we can write the
equation as:
mA vA + mB vB = (mA + mB) v
furthermore, car B was at a stop signal therefore vB = 0,
hence
mA vA + 0 = (mA + mB) v
1800 (vA) = (1800 + 1500) (7.1 m/s)
<span>vA = 13.02 m/s</span>