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2 years ago

Describe three ways that solar energy can be used

Physics

1 answer:

Gemiola [76]2 years ago

6 0

Answer: Heat for making hot water

Heating buildings and cooking.

To generate electricity with solar cells or heat engines, and to take the salt away from sea water.

Explanation:

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A person is standing on a level floor. His head, upper

BabaBlast [244]

Answer:

$y_{cg} = 1.03 m$

Explanation:

Given data:

weigh (head+arms + head) w_1 = 438 N

centre of gravity y_1= 1.28 m

weigh (upper leg) w_2 = 144 N

Center of gravity y_2 = 0.760 m

weigh ( lower leg + feet) = 87 N

centre of gravity = y_3 = 0.250 m

location of center of gravity $= \frac{w_1 y_1 + w_2 y_2 + w_3 y_3}{w_1 +W_2 +w_3}$

$y_{cg} = \frac{438 \times 1.28 + 144\times 0.760 + 87 \times 0.250}{438+144+87}$

$y_{cg} = 1.03 m$

8 0

4 years ago

Which of the following is not true about the Law of Conservation of Energy?

SVEN [57.7K]

By definition, the law of conservation of energy states that:

Ei = Ef

Where,

Ei: initial energy

Ef: final energy

Therefore, no matter the type of energy, always the final energy is equal to the final energy.

Energy can be transformed into another type of energy. For example, the potential energy can be transformed into kinetic energy.

Also, energy is not created, nor destroyed.

Answer:

The following is not true about the Law of Conservation of Energy:

A. It states that the total energy in the universe keeps increasing.

8 0

3 years ago

Read 2 more answers

A solid block of metal is at its melting temperature. it takes 24j to melt 6kg of a metal. what is the latent heat of fusion of

Marina86 [1]

The Latent heat of fusion is also known as the Enthalpy of Fusion. It is a kind pf change in enthalpy.

<h3>Brief explanation of Latent Heat of Fusion? </h3>

The latent heat of fusion, is the change in enthalpy that takes place when energy, typically heat, is provided to a specific quantity of a substance to causes it to change from a solid state to a liquid state at a constant pressure.

For instance, 1 kilogram of ice melts at 0 °C at a variety of pressures, absorbing 333.55 kJ of energy without causing a change in temperature.

The heat of solidification, which occurs when a substance changes from a liquid to a solid, is equal and opposing.

This energy includes the contribution necessary to displace its surroundings against ambient pressure in order to accommodate any corresponding change in volume.

The melting point or the freezing point, depending on the situation, is the temperature at which the phase transition takes place. Conventionally, unless otherwise stated, the pressure is taken to be 1 atm (101.325 kPa).

<h3>Calculation</h3>

The formula of latent heat of fusion is L= q/m

Here q is the heat provided and m is the mass of the object.

So, L = 24j/6kg

L= 4j/kg

So, the latent heat of fusion is 4 j/kg

To know more about latent Heat of Fusion visit:

brainly.com/question/28044951

#SPJ4

8 0

2 years ago

Contact lenses are designed to be gas permeable in order to allow oxygen to diffuse to the eye. If the edge of a contact lens is

guapka [62]

Answer: A

The diffusion time through the edge is double the diffusion time through the center.

Explanation:

Only the diffusion coefficient, thickness, surface area, distance affects the time it takes a gas such as oxygen to diffuse a given in a medium. The Diffusion time increases with the square of diffusion distance Also, the Increased surface area increases the rate of diffusion or the diffusion time, whereas a thicker membrane reduces the rate of diffusion or time it takes the gas to be permeable. Also, The greater the distance that a substance must travel, the slower the rate of diffusion The diffusion coefficient determines the time it takes a gas to diffuse. Also the Diffusion time is inversely proportional to the diffusion coefficient.

Now, If the edge of a contact lens is double the thickness of the central portion of the lens, then it will take more time for the gas to diffuse through the thicker portion. since its edge is double the central position, then the diffusion time will also be doubled. So Option A is the best answer-

The diffusion time through the edge is double the diffusion time through the center.

6 0

4 years ago

A particle executes simple harmonic motion with an amplitude of 3.00 cm. At what position does its speed equal half of is maximu

Mrac [35]

Answer:

x=±0.026m

Explanation:

In simple harmonic motion the maximum value of the magnitude of velocity

$v_{max}=wA=\sqrt{\frac{k}{m} }A$

The speed as a function of position for simple harmonic oscillator is given by

$v=w\sqrt{A^{2}-x^{2}$

where A is amplitude of motion

Given data

Amplitude A=3 cm =0.03 m

v=(1/2)Vmax

To find

We have asked to find position x does its speed equal half of is maximum speed

Solution

The speed of the particle the maximum speed as:

$v=\frac{V_{max} }{2}\\ w\sqrt{A^{2}-x^{2} }=\frac{wA}{2}\\ A^{2}-x^{2}=\frac{A^{2} }{4}\\ x^{2}=A^{2}- \frac{A^{2} }{4}\\ x^{2}=\frac{3A^{2}}{4} \\x=\sqrt{\frac{3A^{2}}{4}}$

x=±(√3(0.03)/2)

x=±0.026m

5 0

4 years ago