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3 years ago

The moon Phobos orbits Mars (m = 6.42 x 1023 kg) at a distance of 9.38 x 106 m. What is the Phobos' orbital velocity?

Physics

1 answer:

Leya [2.2K]3 years ago

5 0

Answer:

27.9816 x 10^3 is the period of orbit.

Explanation:

T is the period of the orbit

R is the average radius of orbit

G is gravitational constant

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A galaxy whose stars are arranged in a disk with arms that surround a central bulge is a _____ galaxy.

slamgirl [31]

Spiral Galaxy is the answer

7 0

3 years ago

A girl on a bike is moving at a speed of 1.40 m/s at the start of a 2.15 m high and 12.4 m long incline. The total mass is 57.0

musickatia [10]

Answer:

568.16J

Explanation:

V = 1.4 m/s

h = 2.15m

H = 12.4m

M = 57.0kg

Fr = 41.0N

Vb = 6.80m/s

g = 9.8m/s²

K.E at the top + P.E at the top + Work done = K.E at the bottom + frictional force.

½mv² + mgh + W = ½mVb + Fr.H

(½* 57 * 1.4²) + (57 * 9.8 * 2.15) + W = (½ * 57 * 6.8²) + (41 * 12.4)

55.86 + 1202.22 + w = 1317.84 + 508.4

1258.08 + w = 1828.24

W = 1826.24 - 1258.08

W = 568.16J

5 0

3 years ago

The quantity of heat from a chemical reaction comes from

Tomtit [17]

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius

3 0

4 years ago

The diagram below shows the velocity vectors for two cars that are moving relative to each other.

scoundrel [369]

Answer:

The answer is " $5 \ \frac{m}{s} \ west$ "

Explanation:

$\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\$

velocity of car | respect to car :

$\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\$

$=\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west$

7 0

3 years ago

It takes 0.16 g of helium (He) to fill a balloon. How many grams of nitrogen (N2) would be required to fill the balloon to the s

svet-max [94.6K]

<u>Answer:</u> The mass of nitrogen gas required to fill the balloon is 1.12 grams.

<u>Explanation:</u>

We are given:

Mass of helium gas = 0.16 g

We need to calculate the mass of nitrogen gas that can fill the balloon at same pressure, volume and temperature. This means that the moles of both the gases filling up balloon will be same.

So, to calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of Helium = 0.16 g

Molar mass of helium = 4.00 g/mol

Putting values in above equation, we get:

$\text{Moles of helium}=\frac{0.16g}{4g/mol}=0.04mol$

Now, calculating the mass of nitrogen gas using same above equation, we get:

Moles of nitrogen gas = 0.04 moles

Molar mass of nitrogen gas = 28.01 g/mol

Putting values in above equation, we get:

$0.04mol=\frac{\text{Mass of }N_2}{28.01g/mol}\\\\\text{Mass of }N_2=1.12g$

Hence, the mass of nitrogen gas required to fill the balloon is 1.12 grams.

8 0

4 years ago