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3 years ago

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Use a graphing utility to approximate the real solutions, i any, of the given equation rounded to two decimal places. All soluti

ons lie between 10 and 10 x3-5x+3-0 What are the approximate real solutions

1 answer:

Readme [11.4K]3 years ago

4 0

Use this f(x)=x^4-3x^3+6x-2

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4 years ago

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3 years ago

Solving Rational equations. LCD method. Show work. Image attached.

Dmitry [639]

Answer:

$b=1$

Step-by-step explanation:

The given rational equation is

$\frac{2b-5}{b-2} -2=\frac{3}{b+2}$

The Least Common Denominator is $(b+2)(b-2)$ .

Multiply each term in the equation by the LCD.

$(b+2)(b-2)\times \frac{2b-5}{b-2} -(b+2)(b-2)\times2=(b+2)(b-2)\times\frac{3}{b+2}$

Simplify;

$(b+2)\times \frac{2b-5}{1} -2(b+2)(b-2)=(b-2)\times\frac{3}{1}$

$(b+2)(2b-5) -2(b+2)(b-2)=3(b-2)$

Expand and group similar terms

$2b^2-5b+4b-10 -2(b^2-4)=3b-6$

$2b^2-5b+4b-10 -2b^2+8=3b-6$

$-b-2=3b-6$

$3b+b=-2+6$

$4b=4$

$b=1$

3 0

3 years ago