Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.
Answer:
The answer to your question is: second option
Step-by-step explanation:
g(x) = x + 4
- This function is linear because the power of x is 1, if the power were a different number it would not be linear.
- As the sign of 4 is positive, it means that the function is translated 4 units up.
- A constant is when there is a number, for example +4 or -4, in this example the function also has a letter "X" so it is not a constant.
Ok so to solve for percent off
percent off means discount
so therefor we need to find how much was discounted
30-20.10=9.90
so we see that 9.90 was discounted
to find the percent we do
discount/total=percent discount
9.90/30=0.33
percent means parts out of 100
0.33/1 times 100/100=33/100=33%
answer is 33% discout
Around 10 of not a clue. Good luck on that!
Answer: The proportion that will qualify is 0.0314 or 3.14%.
First, we need to find the z-score of a time of 128 seconds. To do this, we find the difference of the mean and score and divide by the standard deviation.
(128 - 141) / 7 = -1.86
Now, use a standard normal distribution table to determine the percent below a z-score of -1.86. That value is 0.0314 or 3.14%.
