Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
Answer: 22 i think
Step-by-step explanation:
add all sides together
4000
by using pythagoras theorem h^2=p^2+b^2
The complete question in the attached figure
we know that
[volume of the box]=L*W*H
volume=24 cm³
case A) 10 cm long 4 cm wide and 10 cm hight
volume=10*4*10-----> volume=400 cm³
400 cm³ is not 24 cm³
case B) 2 cm long 2 cm wide and 6 cm high
volume=2*2*6-----> volume=24 cm³
24 cm³ is equal to 24 cm³----> could be the dimensions of the box
case C) 8 cm long 3 cm wide and 1 cm high
volume=8*3*1-----> volume=24 cm³
24 cm³ is equal to 24 cm³------> could be the dimensions of the box
the answer iscase B) 2 cm long 2 cm wide and 6 cm highcase C) 8 cm long 3 cm wide and 1 cm high