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Verdich [7]
3 years ago
10

A student has a container with a volume of 0.5 liter. He estimates the volume to be 0.4 liter. By what percent is the​ student's

estimate​ off?
Mathematics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

20

Step-by-step explanation:

0.5-0.4=0.1,0.1/0.5×100= 20

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Determine whether f(x) = 4x^2 – 16x + 6 has a maximum or a minimum value and find that value.
bulgar [2K]

Answer:

minium:-2................

5 0
3 years ago
Read 2 more answers
Please help me i really need help please help please
solong [7]

Answer:

3.605 ft is the answer.

Step-by-step explanation:

Applying Pythagoras theorem,

a^2 + b^2 = c^2

2^2 + 3^2 = c^2

4 + 9 = c^2

13 = c^2

3.605 = c

therefore, the answer is 3.605.

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8 0
3 years ago
Find Each product
Law Incorporation [45]

Answer:

2.b

3.a

4.c

Step-by-step explanation:

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5 0
2 years ago
Pleaassseeeee helpppppp,,,,!!!!!!
Flura [38]
Surface Area (SA) of a Cylinder formula:
SA = 2*pi*r*h+2*pi*r^2
If you fill in the formula:
SA = 2*3.14*2*9+2*3.14*2^2
Simplify:
SA = 6.28*18+6.28*4
SA = 113.04 + 25.12
SA = 138.16 in
I hope I helped 
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6 0
3 years ago
Find the surface area of the composite solid and round to the nearest tenth. Explain your answer.
Orlov [11]
Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.

so, for the rectangle's sides,

front and back are two 6x3 rectangles

left and right are two 6x3 rectangles

the bottom part is a 6x6 rectangle

now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.

now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.

so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,

\bf \stackrel{lateral~rectangles}{4(6\cdot 3)}~~+~~\stackrel{bottom~rectangle}{(6\cdot 6)}~~+~~\stackrel{triangles}{4\left( \cfrac{1}{2}(6)(4) \right)}
7 0
3 years ago
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