Answer:
Explanation:
Given that,
Mass = 5kg of water
Initial pressure P•i = 5bar = 500 kPa
Pressure is constant P = 5bar
Initial temperature T•i = 360°C
Heat transferred Q = 2660 KJ
Kinetic and potential energy are negligible
a. Final volume
The initial enthalpy and specific volume can be determine from the steam table.
h•1 = 3188.83 KJ/kg
v•1 = 0.5796 m³/kg.
So, we can calculate the final enthalpy by using
Q = m(h2—h•1)
2660 = 5 (h2—3188.83)
2660/5 = h2—3188.83
h2 — 3188.83 = 532
h2 = 520 + 3188.83
h2 = 3720.83 KJ/kg.
Using steam table, we can determine the final temperature and final specific volume
T•f = 608°C
v•f = 0.8115 m³/kg
Then, specific volume = volume /mass
v•f = v2/m
v2 = vf × m
v2 = 0.8115 × 5
v2 = 4.0575m³
b. Workdone?
W = m•P•(vf —vi)
W = 5 × 500(0.8115 — 0.5796)
W = 579.75 KJ
Answer:d
Explanation:
All the given situations are possible because
(a)When particles are oppositely charged then they attract each other
(b)One is Positively charged and other is uncharged: Charged particle will induce charges of opposite nature to attract the other particle
(c)Negatively charged particles will induce the positive charge in the uncharged particle to attract the initially uncharged particle.
exothermic
Explanation:
negative means it's losing energy
Answer:
the right answer is density of metal v1.v2
As the two spheres are brought into contact, the charge on the charged sphere is distributed equally between the two spheres. Now they both have the same charge. Because they have the same charge they are going to repel each other.
The two spheres are going to experience repulsion.
hope this helps :)