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3 years ago

you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy

Physics

1 answer:

Len [333]3 years ago

8 0

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

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A boxcar traveling at 12 m/s approaches a string of 5 identical boxcars sitting stationary on the track. The moving boxcar colli

olga2289 [7]

Answer:

2 m/s

Explanation:

Momentum is conserved:

mv = MV

where m is mass of the boxcar, v is its initial velocity, M is the mass of all six box cars, and V is the final velocity.

v = 12 m/s, and M = 6m, so:

m (12 m/s) = 6m V

12 m/s = 6V

V = 2 m/s

6 0

3 years ago

The time constant of a simple RL circuit is defined as _______. We say that R is the resistance of the circuit and L is the indu

Gennadij [26K]

Answer:

The correct answer will be " $\tau =\frac{L}{R}$ ".

Explanation:

The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5 $\tau$ as well as five-time constants.

It would be calculated in seconds by:

⇒ $\tau=\frac{L}{R}$

, where

R seems to be the resistor function in ohms.
L seems to be the inductor function in Henries.

5 0

3 years ago

3. Riddle:

beks73 [17]

Answer:

The answer is charcoal

3 0

3 years ago

Read 2 more answers

An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su

sergiy2304 [10]

To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.

Mathematically this pressure is given under the formula

$P_h = \rho g h$

Where,

$\rho$ = Density

h = Height

g = Gravitational acceleration

Rearranging in terms of g

$g = \frac{P_h}{\rho h}$

our values are given as

$P_h = 1.1 atm (\frac{101325Pa}{1atm}) = 111457.5Pa$

$\rho = 1000kg/m^3$

$h = 12.3m$

Replacing we have

$g = \frac{111457.5}{(1000)(12.3)}$

$g = 9.061m/s^2$

Therefore the gravitational acceleration on the planet's surface is $9.061m/s^2$ (Almost the gravity of the Earth)

3 0

3 years ago

At 13:20 on the last Friday in September, 1989 a frantic call was received at the local police station. There had been a serious

astraxan [27]

The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

$v^2 = v_o^2 - 2 a x$

Where the acceleration is given by Newton's second law.

fr = m a

The friction force is given by the expression.

fr = μ N

fr = μ mg

Let's Substitute.

μ m g = m a

a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet, dry conditions, etc.

Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.

This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact

$p_o = p_f$ \f

Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision in each direction.

$tan \theta = \frac{p_{01}}{p_{02}}$

$\theta = tan ^{-1} \frac{p_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

Learn more about kinematics and momentum here: brainly.com/question/17304001

5 0

3 years ago