The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver's seat. Part A If the car goes over a b
1 answer:
Answer:
the frequency of the oscillation is 1.5 Hz
Explanation:
Given;
mass of the spring, m = 1500 kg
extention of the spring, x = 5 mm = 5 x 10⁻³ m
mass of the driver = 68 kg
The weight of the driver is calculated as;
F = mg
F = 68 x 9.8 = 666.4 N
The spring constant, k, is calculated as;
k = F/m
k = (666.4 N) / (5 x 10⁻³ m)
k = 133,280 N/m
The angular speed of the spring is calculated;
The frequency of the oscillation is calculated as;
ω = 2πf
f = ω / 2π
f = (9.426) / (2π)
f = 1.5 Hz
Therefore, the frequency of the oscillation is 1.5 Hz
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The <u>albedo</u> is an amount that expresses the percentage of radiation a surface reflects with respect to the incident radiation.
In other words:
This amount allows us to know the level of radiation that <u>reflects</u> a surface compared to the total <u>radiation it receives</u>.
According to this, light surfaces such as snow covered ground or white sand will have a higher albedo than dark surfaces such as carbon covered ground. It is also important to note, the albedo will be higher on glossy surfaces than on matte surfaces.
It should be noted that the albedo of the Earth is on average about , which means that part of the radiation received by the Sun is absorbed and another part reflected back to space.
Answer:
p = 8N/mm2
Explanation:
given data ;
diameter of cylinder = 150 mm
thickness of cylinder = 6 mm
maximum shear stress = 25 MPa
we know that
hoop stress is given as =
axial stress is given as =
maximum shear stress = (hoop stress - axial stress)/2
putting both stress value to get required pressure
t = 6 mm
d = 150 mm
therefore we have pressure
p = 8N/mm2