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Lostsunrise [7]
3 years ago
14

Find the missing side of each triangle.

Mathematics
2 answers:
Bogdan [553]3 years ago
6 0
They answer is 12.t obeys
GalinKa [24]3 years ago
4 0

Answer:

The choice D) 14.7

Step-by-step explanation:

{(5.7)}^{2}  +  {(13.5)}^{2}  =  {x}^{2}  \\ 32.49 + 182.25 =  {x}^{2}  \\  {x}^{2}  = 214.74 \\ x = 14.65 \\ x = 14.7

I hope I helped you^_^

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What is the multiplicative inverse of 1/16 ?
andrey2020 [161]

Answer:

16/1 I think

Step-by-step explanation:

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3 years ago
Write an integer for a profit of $460
yanalaym [24]

Answer:

An integer may be +460 because profit means to increase.  

So the answer is +460.

4 0
3 years ago
What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

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When we distribute and multiply:

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And once we combine like terms:

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8 0
3 years ago
Read 2 more answers
Simplify and Show all of your work please!
Fudgin [204]

Answer:

\Huge \boxed{\mathrm{9}}

Step-by-step explanation:

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Dividing first.

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Multiplying and subtracting.

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7 0
3 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
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