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guapka [62]
2 years ago
5

Yomaro is buying soil for his garden. He needs to fill one pot with 12 cups of soil and another pot with 2 gallons of soil.

Mathematics
1 answer:
SOVA2 [1]2 years ago
3 0

Answer the answer to your question is $7.50

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What is 3.125 as a fraction
iVinArrow [24]
3.125 as a fraction is 25/8
4 0
3 years ago
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Solve the following inequality: –1 + 6(–1 – 3x) > –39 – 2x.    
insens350 [35]
<span>–1 + 6(–1 – 3x) > –39 – 2x. 
</span>-1-6-18x>-39-2x
-7-18x>-39-2x
-18x>-32-2x
-16x>-32
x<2


B. x<2
7 0
3 years ago
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Write the equation for the line that passes theough (-4 , 9) and is parallel to the given line
devlian [24]

Step-by-step explanation:

Equation is y = -3/4x + 12.

3 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 15% of scores B: Scores below the
lisabon 2012 [21]

Answer:

59 to 66

Step-by-step explanation:

Mean test scores = u = 74.2

Standard Deviation = \sigma = 9.6

According to the given data, following is the range of grades:

Grade A: 85% to 100%

Grade B: 55% to 85%

Grade C: 19% to 55%

Grade D: 6% to 19%

Grade F: 0% to 6%

So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.

6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for  0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)

The formula for z score is:

z=\frac{x-u}{\sigma}

For z = -1.56, we get:

-1.56=\frac{x-74.2}{9.6}\\\\ x = 59

For z = -0.88, we get:

-0.88=\frac{x-74.2}{9.6}\\\\ x = 66

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)

7 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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