Can you explain it more clear because my english is not very good, I want to easy to help you
we are given
worker’s hourly wage is $6.37
number of hours is n
so,
workers earnings in n hours is 6.37*n
so,
so,
option-C.........Answer
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
Step-by-step explanation:
The amount that Rita and Tina each make per hour working as cashiers at a supermarket is $11.
Last week, Rita worked r hours. It means that the amount that Rita made last week, working for r regular hours is 11r. Rita also worked overtime hours during the week, for which she was paid an extra $32 flat wage. It means that the total amount earned by Rita last week was
11r + 32
Last week, Tina worked for t hours. It means that the amount earned by Tina last week was 11t
The expression representing the total weekly wages of both Rita and Tina is
11r + 32 + 11t
