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2 years ago

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In the xy-plane, a line crosses the y-axis at the point (0, 3) and passes through the point (4, 5). Which is the equation of the

line? A) y = 1 2 x + 3 B) y = 2x + 3 C) y = 1 2 x − 4 D) y= 2x − 4

1 answer:

Gelneren [198K]2 years ago

4 0

Answer:D

Step-by-step explanation:

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boyakko [2]

23.93 as a percent is 2393%

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2 years ago

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Solve 2x + 4 > 16<br><br> A. x > 10<br> B. x < 6<br> C. x < 10<br> D. x > 6

Salsk061 [2.6K]

Hey there! :)

2x + 4 > 16

We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.

We can start out by subtracting both sides by 4.

2x + 4 - 4 > 16 - 4

Simplify.

2x > 12

Then, divide both sides by 2.

2x ÷ 2 > 12 ÷ 2

Simplify.

x > 6

Therefore, our answer is D. x > 6

~Hope I helped!~

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3 years ago

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miskamm [114]

Step-by-step explanation:

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3 years ago

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Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(

Inessa05 [86]

Answer:

$2+i$

Step-by-step explanation:

Given the expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

To find:

The expression of above complex number in standard form $a+bi$ .

Solution:

First of all, learn the concept of $i$ (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by $i$ .

Value of $i =\sqrt{-1}$ .

Now, let us consider the given expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i$

So, the given expression in standard form is $2+i$ .

Let us compare with standard form $a+bi$ so we get $a =2, b =1$ .

$\therefore$ The standard form of

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

is: $\bold{2+i}$

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