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3 years ago

Answer the following question, show all work:

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

9+3= 12

It was 9 below zero and then went to three above zero so you had 9 and 3

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(-4,6); slope = -3/4

Ostrovityanka [42]

Answer:

y = - $\frac{3}{4}$ x + 3

Step-by-step explanation:

Assuming you require the equation of the line

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{3}{4}$ , thus

y = - $\frac{3}{4}$ x + c ← is the partial equation

To find c substitute (- 4, 6) into the partial equation

6 = 3 + c ⇒ c = 6 - 3 = 3

y = - $\frac{3}{4}$ x + 3 ← equation of line

3 0

3 years ago

4. Given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E, then p

cricket20 [7]

Answer:

Point E is given by $\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Step-by-step explanation:

Let points C and D be $(x_0,y_0),\,(x_1,y_1)$ and let point E divides it in ratio $m:n$ .

Then coordinates of point E are given by $\left ( \frac{mx_1+nx_0}{m+n},\frac{my_1+ny_0}{m+n} \right )$

Put $m:n=3:4$

Point E is given by $\left ( \frac{3mx_1+4x_0}{3+4},\frac{3y_1+4y_0}{3+4} \right )=\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Now plot point E.

Download pptx

3 0

4 years ago

a rectangular dog kennel is to be constructed alongside a house with 60m of fencing. If the house serves as one side of the kenn

Basile [38]

Answer:

$450\text{ m}^2$ .

Step-by-step explanation:

Let x represent side of kennel opposite to house and y represent other sides.

We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.

Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:

$x+y+y=60$

$x+2y=60$

Let us solve for x.

$x+2y-2y=60-2y$

$x=60-2y$

The area of the kennel would be product of its sides that is:

$\text{Area}=x\cdot y$

Now, we will substitute $x=60-2y$ in area equation as:

$A(y)=(60-2y)\cdot y$

$A(y)=60y-2y^2$

Let us find the derivative as shown below:

$A'(y)=60-4y$

Now, we will set derivative equal to 0 and solve for y.

$60-4y=0$

$60=4y$

$\frac{60}{4}=\frac{4y}{4}$

$y=15$

Upon substituting $y=15$ in area function, we will greatest possible area.

$A(y)=60y-2y^2$

$A(15)=60(15)-2(15)^2$

$A(15)=900-2(225)$

$A(15)=900-450$

$A(y)=450$

Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.

5 0

3 years ago

You want to deliver a package to japan.the fed ex delivery service charges a $15 flat fee plus $2 per additional kilogram. You c

Blababa [14]

Depending on how heavy the package is, you should take the Fed Ex if the package is heavy, and the UPS for something that is small

7 0

3 years ago

What is the sum of the infinite geometric series?

Gennadij [26K]

Answer: An infinite geometric series is the sum of an infinite geometric sequence . This series would have no last term. The general form of the infinite geometric series is a1+a1r+a1r2+a1r3+... , where a1 is the first term and r is the common ratio. We can find the sum of all finite geometric series.

Step-by-step explanation:

5 0

3 years ago