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3 years ago

Evaluate the exponent expression for a = 1 and b = -2

Mathematics

2 answers:

shutvik [7]3 years ago

8 0

1/16 hope this helps

iVinArrow [24]3 years ago

5 0

Answer:

D) 1/16

Step-by-step explanation:

use brackets

follow bedmas rule

B - brackets

E - exponent

D - division

M - multiplication

A - addition

S - subtraction

working is shown in the diagram.

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A rental car agency charges $240.00 per week plus $0.15 per mile to rent a car. How many miles can you travel in one week for $3

statuscvo [17]

Answer: In a week you can travel 941 miles

Step-by-step explanation:

$240+0.15m=$381

Subtract $240 on both sides:

$240-$240+0.15m=$381-$240

0.15m=$141

Divide 0.15 on both sides:

0.15m/0.15=141/0.15

m=941 miles

5 0

3 years ago

at the movies, la quinta paid for drinks and popcorn for herself and her two children. she spend twice as much on popcorn as on

jarptica [38.1K]

Answer:

Step-by-step explanation:

let the amount spent on popcorn be x and amount spent on drinks be y

If the total bill paid is $17.94, then x+y = $17.94

If she spend twice as much on popcorn as on drinks, then y = 2x

Substitute y = 2x into the original equation

x+y = $17.94

x + 2x = $17.94

3x = $17.94

x = $17.94/3

x = $5.98

Since y = 2x

y = 2($5.98)

y = $11.96

Therefore she spent $5.98 on popcorn and $11.96 on drinks

4 0

3 years ago

Jaylee bought a pair of shoes and are seems to receive some below from the store she's trying to figure out the sales tax rate t

Anna35 [415]

Answer:

28.62*0.057=1.63134

so about 1.63

Hope This Helps!!!

3 0

3 years ago

A line passes through (−2, 5) and has slope 13 . What is an equation of the line in point-slope form

ruslelena [56]

Y - y1 = m(x - x1)
slope(m) = 13
(-2,5)...x1 = -2 and y1 = 5
sub...pay attention to ur signs
y - 5 = 13(x - (-2)...not done yet
y - 5 = 13(x + 2) <== point slope form

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20%5C%200%7D%20%5Cfrac%7B%5Csqrt%7Bcos2x%7D-%5Csqrt%5B3%5D%7Bcos3x%7D%20%7D%7

salantis [7]

Answer:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

L'Hopital's Rule

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}$

When we directly plug in x = 0, we see that we would have an indeterminate form:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}$

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}$

Plugging in x = 0 again, we would get:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}$

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}$

Substitute in x = 0 once more:

$\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}$

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0

3 years ago