Question

If ∠3 = 4 + 20 and ∠5 = 6 + 10, what value of x proves that ||?

Answer 1

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Given values :

Angle 3 = 4x + 20

Angle 5 = 6x + 10

and, we can observe from the figure that if Angle 3 is equal to Angle 5, then line s will be parallel to line r, because they form pair of alternate interior angles.

• $4x + 20 = 6x + 10$

• $6x - 4x = 20 - 10$

• $2x = 10$

• $x = 5$

hence, the value of x such that the lines s and r will be parallel to each other is 5

correct choice is : A