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3 years ago

What is the partial product for 1,262 x 3

Mathematics

1 answer:

puteri [66]3 years ago

7 0

Step-by-step explanation:

what is THE partial product ? there is a mistake in your problem description.

it must read "what are valid partial products".

1262×3 has the following partial products :

1000×3 = 3000

200×3 = 600

60 × 3 = 180

2×3 = 6

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3786

so, D seems to be the best answer, because both numbers are partial products here.

A, B and C have each only one correct.

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Nikolay [14]

-2.4n-3+-7.8n+2
you combine like terms
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= -10.2n-1

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3 years ago

What is the range of the function? A. (-1,3,5) B. (2,6,8,3,5) C. {3} D. (2,6,8)

Roman55 [17]

Answer:

I think the answer is D. (2,6,8) because if the ones on the right are y - coordinates in the Function then it should be correct. If not sorry

(Range is y - coordinate)

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3 years ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

$\frac{dm}{dt} = -k\cdot m$

b) The general solution is found after separating variables and integrating each sides:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $\tau$ is the time constant and $k = \frac{1}{\tau}$

c) The time constant is:

$\tau = \frac{1690\,yr}{\ln 2}$

$\tau = 2438.155\,yr$

The particular solution of the differential equation is:

$m(t) = 10\cdot e^{-\frac{t}{2438.155} }$

d) The amount of radium after 300 years is:

$m(300) \approx 8.842\,g$

4 0

3 years ago

Read 2 more answers

Can someone help giving branliest to first correct answer

yanalaym [24]

Y=29
Issheishwsihwsuwh i dont know why 8 have to write 20 charcters

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3 years ago

45°

ioda

Answer:

$x = \sqrt{\frac{7}{2} }$

Step-by-step explanation:

Explanation

From given graph

AC = √7

Given angle ∝ = 45°

$cos\alpha = \frac{adjacentside}{Opposite side}$

$cos45 = \frac{x}{\sqrt{7} }$

$\frac{1}{\sqrt{2} } = \frac{x}{\sqrt{7} }$

$x = \frac{\sqrt{7} }{\sqrt{2} }$

$x = \sqrt{\frac{7}{2} }$

x = 1.8708

7 0

3 years ago