Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
2 1/8 is located on the first line after 2 and 1 3/4 i think is located on the 3rd line after one
Step-by-step explanation:
Answer:
The answer is 25.1 or just 25 which ever way they are asking for it
Step-by-step explanation:
Hope that helps
FYI you just need to use the Pythagorean theorem to solve this
A^2 + B^2 = C^2
2.615
Step-by-step explanation:
22 divided by 8