Ask question

Ask question

All categories

3 years ago

9

Two identical cars need to fit into a small garage. The opening is 23 feet 6 inches wide, and there must be at least 3 feet 6 in

ches of clearance between the cars and between the edges of the garage. How wide can the cars be?

1 answer:

arlik [135]3 years ago

4 0

Answer: 23.5 feet

Step-by-step explanation:

You might be interested in

The isotope cobalt-60 has a nuclear mass of 59.933820 u

Lesechka [4]

Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.

The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:

27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u

The actual mass of the nucleus of 60-Co is 59.933820 u.

Mass defect: 60.497220 u - 59.933820 u = 0.563400 u

The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2

(0.563400 u)*(931.5 MeV/u) = 524.807 MeV

3 0

3 years ago

18. Chicken patties are sold in packs of 8. Buns are sold in packs of 10. What is the least number of chicken patties & buns

Nikitich [7]

5 packages of patties = 40

4 packages of buns =40

4 0

3 years ago

Read 2 more answers

Which of the following has the lowest unit price?

RideAnS [48]

I think i is your answer since that is the lowest price

5 0

3 years ago

Which number line shows all the values of a that make the inequality - 3x +1 < 7 true?

GrogVix [38]

Answer:

Third option

Step-by-step explanation:

5 0

3 years ago

Write the equation of the line shown in point-slope form. (2,1) (3,8)

Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ ..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

$(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)$

$(y -8) = \frac{(- 7)}{(-1)}(x-3)$

y – 8 = 7(x – 3)

y – 8 = 7x – 21

7x – y = 21 – 8

7x – y = 13

Hence, the line equation that passes through the given points is 7x – y = 13

3 0

4 years ago