Answer:
N = 9
M = 87.11
Step-by-step explanation:
According to the situation, the data provided and the solution are as follows
The scores for the student in the classroom is
= 88 88 92 88 88 72 96 88 84
The different student's number of scores is 9
The solution of new n and M is shown below:-
Sample size (n) = 9
Sample mean (m) is
![= \frac{Sum\ of\ all\ data\ values}{Sample\ size}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7BSum%5C%20of%5C%20all%5C%20data%5C%20values%7D%7BSample%5C%20size%7D)
= ![\frac{88 + 88 + 92 + 88 + 88 + 72 + 96 + 88 + 84}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B88%20%2B%2088%20%2B%2092%20%2B%2088%20%2B%2088%20%2B%2072%20%2B%2096%20%2B%2088%20%2B%2084%7D%7B9%7D)
![= \frac{784}{9}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B784%7D%7B9%7D)
= 87.11
It is the lateral edge as it is an edge and it is on the lateral area.
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=![50\°](https://tex.z-dn.net/?f=50%5C%C2%B0)
∠FGH=
-----> equation A
![arc\ FEH+arc\ FH=360\°](https://tex.z-dn.net/?f=arc%5C%20FEH%2Barc%5C%20FH%3D360%5C%C2%B0)
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
![100\°=2arc\ FEH-360\°](https://tex.z-dn.net/?f=100%5C%C2%B0%3D2arc%5C%20FEH-360%5C%C2%B0)
![2arc\ FEH=360\°+100\°](https://tex.z-dn.net/?f=2arc%5C%20FEH%3D360%5C%C2%B0%2B100%5C%C2%B0)
![arc\ FEH=230\°](https://tex.z-dn.net/?f=arc%5C%20FEH%3D230%5C%C2%B0)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to ![230\°](https://tex.z-dn.net/?f=230%5C%C2%B0)