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finlep [7]
3 years ago
6

Is x + 1 a factor of the polynomial function p(x) = x^3 – 7x^2 - 10x + 16​

Mathematics
2 answers:
OLga [1]3 years ago
5 0

Answer:

slove it by yourself dear

Step-by-step explanation:

mark me <em>brainlists</em><em> </em><em>hli</em><em> </em>

vagabundo [1.1K]3 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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3 years ago
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Evaluate the summation from n equals 1 to infinity of the quotient of 3 and 2 raised the quantity n minus 1 power
Shalnov [3]

Answer:

3*∑ (1/2)^n = 6

Step-by-step explanation:

We have the summation from n = 1 to n = ∞, for:

∑ 3/(2)^(n - 1)

We know that the summation between k = 0, and k = N - 1 for:

∑ r^k = (1 - r^N)/(1 - r)

if we have the summation between k = 0 and k = ∞ - 1 = ∞

(here we used that ∞ is really big, then ∞ - 1 = ∞)

In the numerator we will have the term r^∞, if 0 < r < 1, then r^∞ = 0.

Then if we assume that 0 < r < 1 we can write:

∑ r^k =  1/(1 - r)

In our case, we can rewrite our summation as:

3*∑ (1/2)^n

for n = 0 to  n = ∞

You can see that i changed the limits for n, this does not really matter because we are summing between a number and infinity, the only thing you need to take care is that now the power is n, instead of (n - 1)

Then we have r = (1/2) which is clearly smaller than 1.

then (1/2)

Then this summation is equal to:

3*∑ (1/2)^n = 3*( 1/(1 - 1/2)) = 3*( 1/( 2/2 - 1/2)) = 3*( 1/(1/2)) = 3*2 = 6

3*∑ (1/2)^n = 6

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3 years ago
Im in love with men and love men in my butt it feels so good
kari74 [83]

Answer:

period

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2 years ago
Can somebody help me with these, i will mark you brainliest :)
Diano4ka-milaya [45]

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Step-by-step explanation:

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natulia [17]
3:5=x:50

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therefore 80 = 8x

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3 years ago
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