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expeople1 [14]
2 years ago
7

Marco and Drew stacked boxes on a shelf. Marco lifted 9 boxes of equal weight. Drew lifted 14 boxes, but Drew's boxes of equal w

eight, but Drew's boxes each weighed 8 lb less than Nathan's boxes.
Together, they lifted a total of 233 pounds.

What was the weight of one of Marco's boxes?


5 lb

8 lb

10 lb

15 lb
Mathematics
1 answer:
elixir [45]2 years ago
6 0

Answer:

Marco's boxes weigh 15 lbs.

Step-by-step explanation:

9x + 14(x - 8) = 233

9x + 14x - 112 = 233

23x = 345

x = 15

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3 years ago
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paige spent $7.55 on some report covers and one lanyard at the spirit shop. Each report cover costs $0.35 and the layard cost $6
fomenos

Answer:

The answer is 3.

Step-by-step explanation:

7.55-6.50=1.05

1.05/.35=3

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3 years ago
If f(x) = 3x + 3, g(x) = 3x + 3, and h(x) = x + 3, what is [g o f o h](–5)?
emmasim [6.3K]
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8 0
3 years ago
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Does anyone know the questions for the dba of pre algebra 2.00?
Oksanka [162]

Answer:

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6 0
2 years ago
Please Help. Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy
velikii [3]

Answer:

1. The equation is given as

324 = 220 +135 + C

2. We have 166 As the correct answer but is not in the option

Step-by-step explanation:

We are been given the following values

No. of trophies = 3

Total Legos required for all trophies = 324

No. of Legos for largest trophy(A) = 220

No. of Legos for smallest trophy(B) = 135

No. of Legos required for final trophy(C) which is unknown

Total legos will addition of everything

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]

Substituting the values

324 = 220 +135 + C

Making C subject of formula

324 = 355 + C

324 - 355 = C

-31 = C

135 + 31 = 166

We have 166 As the answer

8 0
3 years ago
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