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3 years ago

0.250 moles of NaCl is dissolved in 0.850 L of solution. What is the molar concentration?

Chemistry

1 answer:

Nuetrik [128]3 years ago

6 0

Considering the definition of molarity, the molar concentration is 0.294 $\frac{moles}{liter}$ .

Molarity reflects the concentration of a solution indicating the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{amount of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

In this case, you know:

amount of moles of solute= 0.250 moles
volume= 0.850 L

Replacing in the definition of molarity:

$molarity=\frac{0.250 moles}{0.850 L}$

Solving:

molarity= 0.294 $\frac{moles}{liter}$

Finally, the molar concentration is 0.294 $\frac{moles}{liter}$ .

Learn more about molarity with this example: brainly.com/question/15406534?referrer=searchResults

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3 years ago

Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3

Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

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3 years ago

Write the following elements in increasing order of atomic radius.<br> Ca, Mg, Be, Sr

Free_Kalibri [48]

Answer:

In increasing order:

Sr, Ca, Mg, Br

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3 years ago

6. Why does the sun seem to change position in the sky?

Dafna11 [192]

A. Earth’s Rotation

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3 years ago

What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr

Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The solution will be 0.27M hydrochloric acid

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3 years ago