Answer:
a
No
b
100 mm Hg
Explanation:
From the question we are told that
The vapor pressure of CHCl3, is 
The temperature of CHCl3 is 
The volume of the container is 
The temperature of the container is 
The mass of CHCl3 is m = 0.380 g
Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as
Here M is the molar mass of CHCl3 with the value 
=> 
=> 
Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as
Here R is the gas constant with value 
So
Given that the number of moles of CHCl3 evaporated is less than the number of moles of CHCl3 initially present , then it mean s that not all the liquid evaporated
At equilibrium the temperature of CHCl3 will be equal to the pressure of air so the pressure at equilibrium is 100 mmHg
Answer:
<h2>Density = 1.67 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 50 g
volume = 30 mL
Substitute the values into the above formula and solve for the density
That's
Wr have the final answer as
<h3>Density = 1.67 g/mL</h3>
Hope this helps you
<u>Answer:</u>
(A)
Density = Mass / Volume
So
Mass = Density × Volume
Mole ratio of toluene : Oxygen is 1 : 9
(B)
1 mole of Toluene produces 7 moles of 
gas and 4 moles of 
Vapour
So the mole ratio is 1 : 11
(C)
1mole contains 
molecules
Answer:
Most viscous to least viscous: 
Explanation:
For hydrocarbons, viscosity increases with increasing molar mass. Because increasing molar mass signifies increase in number of electrons in molecules.
We know that in non-polar hydrocarbons, only van der waal intermolecular force exists. Van der waal force is proportional to number of electrons in a molecule.
Therefore with increasing molar mass, van der waal force increases. hence molecules gets more tightly bind with each other resulting increase in viscosity.
Here molar mass order :
Therefore viscosity order :
Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.
