Answer:
1) 40°
2) 140°
3) 140°
5)40°
6)140°
7)140°
8)40°
Step-by-step explanation:
1 = 40 ° <em> [Vertically Opposite angles are equal]</em>
8 = 40 ° <em>[Corresponding Angles are equal]</em>
5 = 8 = 40° <em> [Corresponding Angles are equal]</em>
7 = 180° - 40° = 140° <em>[Supplementary angles sum 180°]</em>
6 = 140° <em> [Vertically Opposite angles are equal]</em>
2 = 140° <em>[Corresponding Angles are equal]</em>
3 = 140 ° <em> [Vertically Opposite angles are equal]</em>
Answer:
The median is 2
Step-by-step explanation:
Here, we want to get the median for the number of pencils
Firstly, we have to write out the numbers that form the box plot ; we have this as;
1,1,1,2,2,2,2,3,3,5
the median is sum of the 5th and 6th term divided by 2
The 5th term is 2
The 6th term is 2
So the median is;
(2 + 2)/2
= 4/2 = 2
1. A quadratic equation has the following form: ax²+bx+c.
2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.
3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:
(x-5)(x+3)=0
4. When you apply the distributive property, you obtain:
x²+3x-5x-15=0
x²-2x-15=0
5. Therefore, the answer is:
x²-2x-15=0
The additive identity property states that for every number a, you have

You're showing this property when you write

Hello!
We use different formulas to calculate the areas of different shape.
RECTANGLE:
To find the area of a rectangle, we must simply multiply its length by its width. The formula for its area is:
A = l × w
SEMICIRCLE:
Since the formula for a circle is pi × r × r, we must use the same formula but divide it in half, because a semicircle is a half circle, which is why its area would also be half of a circle's. The formula for a semicircle's area is:
A = 1/2 pi × r × r
Tip:
Write these formulas down and memorize them so that you don't forget them. You'll have to use these formulas quite often when finding the area of these shapes.