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sashaice [31]
3 years ago
13

When a space shuttle was launched, the astronauts onboard

Physics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

wow that was so dangerous

You might be interested in
While ice skating, you unintentionally crash into a person. Your mass is 60kg
miss Akunina [59]

Answer:

The speed is 6.1m/s with an angle of 56.3 degrees north of east.

Explanation:

We meed to apply the Linear momentum theorem:

m1*vo1+m2*vo2=m1*vf1+m2*vf2\\60*(8.0m/s(East))+80*(9.0m/s(North))=140*vf\\vf=3.4m/s(East)+5.1m/s(North)

The magnitude of the velocity is given by:

v=\sqrt{Veast^2+Vnorth^2} \\v=6.1m/s

and the angle:

\alpha =arctg(\frac{Vnorth}{Veast})\\\alpha=56.3^o

3 0
3 years ago
Light takes 8 minutes to reach the Earth, and the speed of light is 3.0×10^8 m/s. a) What is the orbital speed of the Earth arou
spin [16.1K]

Answer:

(a) 28690 m/s (b) 2.46x10^{33}J

Explanation:

The orbital speed is define as:

v = \frac{2 \pi r}{T}   (1)

Where r is the radius of the trajectory and T is the orbital period.

To determine the orbital speed of the Earth it is necessary to know the orbital period and the radius of the trajectory. That can be done by means of the Kepler's third law and average velocity equation.

The average velocity in a Uniform Rectilinear Motion is defined as:

v = \frac{d}{t}   (2)

Where v is the velocity, d is the covered distance and t is the time.

Equation 2 can be rewritten for d to get:

d = vt   (3)

In this case, v will be the speed of light and t, the 8 minutes that takes to reach the Earth.

The time will be converted to seconds so the units in equation 3 can match:

8min . \frac{60s}{1min} ⇒  480s

t = 480s

Replacing all those values in equation 3 it is gotten:

d = (3.0x10^{8}m/s)(480s)

d = 1.44x10^{11}m

Kepler’s third law is defined as:

T^{2} = r^{3}

Where T is orbital period and r is the radius of the trajectory.

T = \sqrt{r^{3}}

T = \sqrt{(1.44x10^{11}m)^{3}}

It is necessary to pass from meters to astronomical unit (AU), 1 AU is defined as the distance between the Earth and the Sun.

T = \sqrt{1AU}

T = 1AU

That can be expressed in units of years.

T = 1AU . \frac{1year}{1AU}

T = 1year

But there are 31536000 seconds in one year:

T = 1year . \frac{31536000s}{1year}

T = 31536000s

Finally, equation  1 can be used:

v = \frac{2 \pi (1.44x10^{11}m)}{(31536000s)}

v = 28690 m/s

<u>So Earth orbital speed around the Sun is 28690 m/s.</u>

<em>b) What is its kinetic energy?</em>

The kinetic energy is defined as:

E = \frac{1}{2}mv^{2}  (4)

Notice that it is necessary to found the mass of the Earth, that can be done combining the Universal law of gravity and Newton's second law:

F = \frac{GMm}{r^{2}}

ma = \frac{GMm}{r^{2}}  (5)

M will be isolated in equation 5:

M = \frac{r^{2}a}{G}

Where r is the radius of the Earth (6.38x10^{6}m)

M = \frac{(6.38x10^{6}m)^{2}(9.8m/s^{2})}{6.67x10^{-11}kg.m/s^{2}.m^{2}/Kg^{2}})

M = 5.98x10^{24} Kg

E = \frac{1}{2}( 5.98x10^{24} Kg))(28.690m/s)^{2}

E = 2.46x10^{33}Kg.m^{2}/s^{2}

E = 2.46x10^{33}J

<u>Hence, the kinetic energy of Earth is 2.46x10^{33}J.</u>

8 0
3 years ago
The volume of 1 kg of helium in a piston-cylinder device is initially 5 m3. Now helium is compressed to 2 m3 while its pressure
yuradex [85]

Answer:

-540 kJ

Explanation:

P = Pressure which is applied to the piston = 180 kPa

V_2 = Final volume = 2 m³

V_1 = Initial volume = 5 m³

Work done is given by

W=P\Delta V\\\Rightarrow W=P(V_2-V_1)\\\Rightarrow W=180000(2-5)\\\Rightarrow W=180000\times -3\\\Rightarrow W=-540000\ J\\\Rightarrow W=-540\ kJ

The work required to compress helium is -540 kJ

4 0
4 years ago
A bird is standing on an electric transmission line carrying a large amount of current. Find the power dissipated by the bird If
iren [92.7K]

P = 7.3 × 10^-13 Watt

Explanation:

First of all, are you sure that what you have is the right answer?

Anyway, the definition of power dissipated is given by

P = I^2×R

where I is the current and R is the resistance. But we also know from Ohm's law that

V = IR

so we can rewrite the equation for power P as

P = I^2R = I(IR) = VI

= (0.0054 volt)(1.35 × 10^-10 A)

= 7.3 × 10^-13 Watt

3 0
3 years ago
Which of the following climates is most suited for physical weathering?
NemiM [27]
The most suitable answer would be [D] Cool because that is the most common weather to pursue physical weathering.

<em>Hope this helped! :)</em>
3 0
4 years ago
Read 2 more answers
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