Explanation:
Given Data
Total mass=93.5 kg
Rock mass=0.310 kg
Initially wagon speed=0.540 m/s
rock speed=16.5 m/s
To Find
The speed of the wagon
Solution
As the wagon rolls, momentum is given as
P=mv
where
m is mass
v is speed
put the values
P=93.5kg × 0.540 m/s
P =50.49 kg×m/s
Now we have to find the momentum of rock
momentum of rock = mv
momentum of rock = (0.310kg)×(16.5 m/s)
momentum of rock =5.115 kg×m/s
From the conservation of momentum we can find the wagons momentum So
wagon momentum=50.49 -5.115 = 45.375 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
Speed of wagon=45.375/(93.5-0.310)
Speed of wagon= 0.487 m/s
Throwing rock backward,
momentum of wagon = 50.49+5.115 = 55.605 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)
speed of wagon= 0.5967 m/s
Answer: The name is prime meridian and the degree is
0 degrees
Explanation:
The amount of gravitational potential energy acquired by the rock is equal to:
where
m is the mass of the rock
g is the gravitational acceleration
is the increase in height of the rock
Substituting the data of the problem, we find
So, Natalie gave 220.7 J of energy to the rock.
Answer:
10432.19076 m
Explanation:
= Wavelength = 660 nm
d = Diameter of pupils = 6 mm
s = Distance between lights = 1.4 m
L = Distance from observer
From Rayleigh's criteria we have
As is small
So, the equation becomes
The car is 10432.19076 m from me
Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²
m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb
m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg
(b) A 22 g song sparrow, m = 22 g = 0.022 kg
Hence, this is the required solution.