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3 years ago

Which of these is an experiment generally regarded as being first carried out by James Joule?

2 answers:

8 0

1. The correct answer among the choices provided is the third option. Measuring the temperature increase of water from doing work by stirring it is an experiment generally regarded as being first carried out by James Joule.
2. Joule's experiment directly shows that heat is a form of energy. He wanted to make a different way of measuring energy.

marusya05 [52]3 years ago

4 0

Answer 1: The correct answer is: 'measuring the temperature increase of water from doing work stirring it'.

Answer 2: The correct answer is :'Heat is a form of energy'.

Explanation:

In his experiment he took three fluids : water, oil, mercury in an insulating container with stirrer agitated in the fluid.

He measured the amount of work done by the rotating stirrer in the fluid and the temperature rise in the fluid due to the rotation of the stirrer was also observed.

From his observation he concluded that the heat possessed by the fluid and work done on the fluid is directly linked to each other. Which he put down is simple words "heat is a form of energy"

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An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi

elena55 [62]

Answer:

a) $\vec F_{B} = 8.766\times 10^{-14}\,T\,k$ , b) $\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

Explanation:

a) The magnetic force experimented by a particle has the following vectorial form:

$\vec F_{B} = q\cdot \vec v \times \vec B$

The charge of the electron is equal to $-1.602\times 10^{-19}\,C$ . Then, cross product can be solved by using determinants:

$\vec F_{B} = \begin{vmatrix}i&j&k\\-4.165\times 10^{-13}\, C\cdot \frac{m}{s} &-5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = 8.766\times 10^{-14}\,T\,k$

b) The charge of the proton is equal to $1.602\times 10^{-19}\,C$ . Then, cross product has the following determinant:

$\vec F_{B} = \begin{vmatrix}i&j&k\\4.165\times 10^{-13}\, C\cdot \frac{m}{s} &5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

8 0

3 years ago

In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,

Anon25 [30]

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

$F=\dfrac{dP}{dt}$

Therefore force F

$F=\dfrac{\Delta P}{\Delta t}$

$F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N$

F=4040.81 N

Therefore force on the ball will be 4040.81 N

6 0

3 years ago

Equal and opposite forces that act on the same object are called __________ forces. A. balanced B. operative C. neutral D. unbal

gizmo_the_mogwai [7]

<span>Equal and opposite forces that act on the same object are called balanced forces.</span>

6 0

3 years ago

Three resistors of 15.0 ohms, 30.0 ohms, and 60.0 ohms respectively are connected in parallel to an applied potential difference

AVprozaik [17]

A). The drawing looks like a ladder with 4 rungs.
One rung is a 90-volt battery.
The other 3 rungs are the 3 resistors.

b). The equivalent resistance is the reciprocal of (1/15 + 1/30 + 1/60).
That's the reciprocal of 7/60, or about 8.571... ohms.

c). I = V/R = 90 / 8.571... = 10.5 Amperes.

d). The 60-ohm resistor is connected directly across the battery.

Power = V²/R = (90²) / 60 = 135 watts. Better COOL that baby !

4 0

3 years ago

How many grandfather clocks could you power with the same amount of power as is used by a single light bulb?

rosijanka [135]

Yes we can run almost three lakhs of the grandfather clocks to run a single light bulb .

<u>Explanation:</u>

Yes we can run almost three lakhs of the grandfather clocks to run a single light bulb .
In simple words, power can be defined as the work done by the time and the SI unit of the power is Joules per second.
For example in the case of the light bulb, the Incandescent light bulb takes 60 watts per hour.
For example in the case of the clocks, the modern clocks use between 1 and 2 watts power.

3 0

3 years ago