Consider 3 polarizers. Polarizer 1 has a vertical transmission axis and polarizer 3 has a horizontal transmission axis. Taken to
gether, polarizers 1 and 3 are a pair of crossed polarizers. Polarizer 2, with a transmission axis of 300 to the vertical, is placed between polarizers 1 and 3. What is the intensity of light transmission through these polarizers given an initial intensity of light lo?
a. 0.375 lo
b. 0.25 l0
c. 0.18 lo
d. 0.09 lo
e. zero
a. 0.375 lo
b. 0.25 l0
c. 0.18 lo
d. 0.09 lo
e. zero
1 answer:
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Answer: F = 2N
Explanation: If a current i is flowing in a wire of length L lying in a region of magnetic field B, then the magnetic force acting on the wire is given by
F = BIL
Please find the attached file for the solution
Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ =
τ =
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω =
ω =
ω =
A = 0.52 rad/s B = -0.182 rad/s²
Answer:
m = 236212 [kg]
Explanation:
The potential energy can be determined by means of the product of mass by gravity by height. In this way, we have the following equation.
where:
P = potential energy = 3360000000 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1450 [m]
Now, we can clear the mass from the equation above: