Consider 3 polarizers. Polarizer 1 has a vertical transmission axis and polarizer 3 has a horizontal transmission axis. Taken to
gether, polarizers 1 and 3 are a pair of crossed polarizers. Polarizer 2, with a transmission axis of 300 to the vertical, is placed between polarizers 1 and 3. What is the intensity of light transmission through these polarizers given an initial intensity of light lo?
a. 0.375 lo
b. 0.25 l0
c. 0.18 lo
d. 0.09 lo
e. zero
a. 0.375 lo
b. 0.25 l0
c. 0.18 lo
d. 0.09 lo
e. zero
1 answer:
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Answer:
9241.6 W or 12.39318 hp
Explanation:
u = Initial velocity = 0
v = Final velocity
m = Mass
t = Time taken
Energy
Power
Converting to hp
The power developed by the cheetah is 9241.6 W or 12.39318 hp
Answer:
1000 N
Explanation:
First, we need to find the deceleration of the running back, which is given by:
where
v = 0 is his final velocity
u = 5 m/s is his initial velocity
t = 0.5 s is the time taken
Substituting, we have
And now we can calculate the force exerted on the running back, by using Newton's second law:
so, the magnitude of the force is 1000 N.