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Svetlanka [38]
3 years ago
15

Consider 3 polarizers. Polarizer 1 has a vertical transmission axis and polarizer 3 has a horizontal transmission axis. Taken to

gether, polarizers 1 and 3 are a pair of crossed polarizers. Polarizer 2, with a transmission axis of 300 to the vertical, is placed between polarizers 1 and 3. What is the intensity of light transmission through these polarizers given an initial intensity of light lo?
a. 0.375 lo
b. 0.25 l0
c. 0.18 lo
d. 0.09 lo
e. zero

Physics
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

Detailed solution is given below:

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Readme [11.4K]

Between the top of the first and the top of the second loop, the coaster has lost potential energy = mgh, where h = 22.2 - 15 = 7.2m

This energy would have converted to Kinetic. Write out an equation and the masses will cancel out. Does that hint help you to find the solution? If not, I will give you another hint.

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3 years ago
If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of
kherson [118]

Answer:

1 x 10¹⁷

               

Explanation:

Given data:

        Radius of the earth  = 6000km

        Radius of an atom  = 60pm

Now, how many orders is the radius of the earth larger than an atom

Solution:

To solve this problem, let us express both quantity as the same unit;

         1000m  = 1km

    6000km  = 6000 x 10³m   =  6 x 10⁶m

    60pm;

            1 x 10⁻¹²m  = 1pm

    60pm  = 60 x  1 x 10⁻¹²m  = 6 x 10⁻¹¹m

Now;

The order:   \frac{6 x 10^{6} }{6 x 10^{-11} }   = 1 x 10¹⁷

               

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2 years ago
Where are you likely to find a cooling plant located in the ductwork? A. A medium-sized office B. A large factory C. A single fa
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Answer:

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Explanation:

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3 years ago
Hello I need help its due today!
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Explanation:

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2 years ago
In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initi
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Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = \frac{K*q}{d^2}*d = \frac{K*q}{d}

d = \frac{K*q}{V}

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

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3 years ago
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