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alukav5142 [94]
3 years ago
7

What is the midpoint of the x-intercepts of f(x) = (x - 2)(x – 4)?

Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

1

Step-by-step explanation:

because it is.

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This is lines, functions and systems. Graph the line with slope 1 passing through the point (4, 2).
anzhelika [568]

To graph the line we need two points; we already have one the point (4,2) now we need to find another one; to do this we get the equation of the line given by:

y-y_1=m(x-x_1)

where m is the slope and (x1,y1) are a point throught the line. Plugging the values given we have:

\begin{gathered} y-2=1(x-4) \\ y-2=x-4 \\ y=x-4+2 \\ y=x-2 \end{gathered}

Now we give a value to x and find the corresponding y. If x=0, then:

y=-2

hence we have the point (0,-2).

Now that we have two points (0,-2) and (4,2) we graph them on the plane and join them with a straight line, hence the graph is:

5 0
1 year ago
The height (h), in feet, of a balloon is calculated by using the equation h equals 3t + 2 where t is the time,in seconds. What i
navik [9.2K]
ANSWER: 92

EXPLANATION:
You plug in 30 where t us and solve.
3(30)+2=92
4 0
3 years ago
Step 2: Calculate the measures of SPREAD for rs. Hampton's data in the dot plot. Show your work
GrogVix [38]

Answer:

-12

Step-by-step explanation:

don't rlly have an explanation

8 0
3 years ago
segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc
Elan Coil [88]

Answer:

The magnetic field is B = 3.87 *10^{-6} \ T

Direction is inward

 

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

      The radius of  BC is  r_{BC} =  30 \ cm  =  0.30 \ m

      The radius of  DA is r _{DA} =  20 \ cm =  0.20 \ m

      The length of CD is  r_{CD} =  10 cm =  0.1 \ m

      The length of AB is  r_{AB} =  10 cm =  0.1 \ m

      The current is  I  =  11.4A

The magnetic field is mathematically represented as

      B =  B_{BC} +  B_{DA} + B_{CD} + B_{AB}

       B =  \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]

        Where

                 \theta_{BC} = \theta_{DA} =  \frac{2\pi}{3}

Where  \frac{2 \pi}{3}  =  120^o

                \theta_{CD} = \theta_{AB}  =  0^o

so

        B =  \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]

         B = 3.87 *10^{-6} \ T

The direction is into the page

    This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule  the direction of current is perpendicular to the direction of magnetic field so since  current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0
3 years ago
AB=25 , BD=4, Solve for the radius?<br> Please help!!!!!
Alex787 [66]

9514 1404 393

Answer:

  r = 14.5

Step-by-step explanation:

AD is the perpendicular bisector of chord EC, so is the diameter of the circle. The radius is half the diameter.

  r = AD/2 = (AB +BD)/2 = (25 +4)/2 = 29/2

  r = 14.5

__

Segments BE and BC are 10 = √(25·4)

4 0
3 years ago
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