Answer:
Given :-
Initial Velocity (u) = 5 m/s
Final Velocity (v) = 15 m/s
Time (t) = 7.5 seconds
To Find :-
Distance (s) = ?
Solution :-
First of all we will find the acceleration of car :
→ Acceleration = Final Velocity - Initial Velocity ÷ Time
→ Acceleration = 15 - 5 ÷ 7.5
→ Acceleration = 10 ÷ 7.5
→ Acceleration = 1.3 m/s²
Now, by using Second equation of motion we can find distance travelled by the car :
→ s = ut + ½ at²
→ s = 5 × 7.5 + ½ × 1.3 × (7.5)²
→ s = 37.5 + ½ × 1.3 × 56.25
→ s = 37.5 + 1.3 × 28.125
→ s = 37.5 + 29.425
→ s = 66.925 m
Therefore,the distance travelled by the car is 66.925 m.
