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3 years ago

Which famous scientist is associated with the force of gravity?

Physics

1 answer:

jenyasd209 [6]3 years ago

7 0

Answer:

Isaac Newton

Explanation:

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A motorcyclist travelling at 30m/s starts to apply his brake when he is 50m from the traffic light that has just turned red .if

Marat540 [252]

Answer:

9m/s²

Explanation:

Given parameters:

Initial velocity = 30m/s

Final velocity = 0m/s

Distance traveled = 50m

Unknown:

Deceleration = ?

Solution:

To solve this problem, we apply the proper motion equation;

V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

Insert the parameters and solve;

0² = 30² + 2(a)50

-900 = 100a

a = -9m/s²

The negative value indicates deceleration.

The motorcycle decelerates at a rate of 9m/s²

3 0

3 years ago

A car travels at a constant speed of 40 miles per hour down the street for around 0.25 hours. What is its acceleration?

forsale [732]

It’s acceleration is 0 if it was traveling at a constant speed

5 0

3 years ago

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A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler

Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(525\ m/s)^2}{5200\ m}$

$a=53.004\ m/s^2$

We know that, the value of g is, $g=9.8\ m/s^2$

$\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4$

$a=5.4\times g$

So, the acceleration of the plane is 5.4 g. Hence, this is the required solution.

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3 years ago

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Butoxors [25]

Same number of valence electrons

3 0

4 years ago

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Bats can detect small objects such as insects that are of a size on the order of a wavelength. if bats emit a chirp at a frequen

crimeas [40]

The smallest size of the insect that the bats can detect corresponds to the wavelength of the chirp they emit.

Their chirp has a frequency of
$f=69.3 kHz=69.3 \cdot 10^3 Hz$
and the speed of the chirp is equal to the speed of sound in air:
$v=330 m/s$
Therefore the wavelength of the chirp is
$\lambda= \frac{v}{f}= \frac{330 m/s}{69.3 \cdot 10^3 Hz}=4.76 \cdot 10^{-3} m$
which corresponds to a size of 4.76 mm.

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3 years ago