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Nataly [62]
3 years ago
10

A wave travels through a medium because

Physics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

Option b. the wave s energy passes from particle to particle.

Explanation:

A wave is an propagation of energy along a medium. Waves need a medium in order for them to travel from one point or another. A wave is a particulate transfer of motion from one point to another. A very good example of the need of a medium is regarding sound. Sound cannot travel through a vacuum. This is because there are no air molecules to transfer the energy of the sound propagation. Hence no sound travels through the vacuum. The particle to particle interaction and vibration results in the transfer of energy in a wave propagation.

Amanda [17]3 years ago
5 0

in case you dont want to read the answer is B

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The form of energy that can move from place to place across the universe is . On Earth, the main source of this energy is .
serg [7]

The form of energy that can move from place to place across the universe is light energy. On earth, the main source of this energy is Sun. Most of the light energy comes from the sun because it is the primary source of all the energies. The food, fossil fuels, movement of winds, etc all exists due to Sun. Without sun, there won't be any light energy on the earth. In all the processes which occur on earth has a direct or indirect involvement of light energy which comes from sun.

5 0
2 years ago
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Which event is an example of melting?
qaws [65]

Answer:

welding metal

Explanation:

5 0
2 years ago
Which best explains how an object at rest deep in space and far from any massive body behaves compared to an object in free fall
7nadin3 [17]

Answer: They behave the same because, according to the principle of equivalence, the laws of physics work the same in all frames of reference.

Explanation:

According to the equivalence principle postulated by Einstein's Theory of General Relativity, acceleration in space and gravity on Earth have the same effects on objects.

To understand it better, regarding to the equivalence principle, Einstein formulated the following:  

A gravitational force and an acceleration in the opposite direction are equivalent, both have indistinguishable effects.  Because the laws of physics must be accomplished in all frames of reference.

Hence, according to general relativity, gravitational force and acceleration in the opposite direction (an object in free fall, for example) have the same effect.  This makes sense if we deal with gravity not as a mysterious atractive force but as a geometric effect of matter on spacetime that causes its deformation.

3 0
3 years ago
Which formula can be used to solve problems related to the first law of thermodynamics?
docker41 [41]

Answer: The formula used to solve the problems related to first law of thermodynamics is \Delta U=Q+W

Explanation:

First law of thermodynamics states that the total energy of the system remains conserved. Energy can neither be destroyed, nor be created but it can only be transformed into one form to another.

Its implication is any change in the internal energy will be either due to heat energy or work energy.

Mathematically,

\Delta U=Q+W

where, Q = heat energy

W = work energy

\Delta U = Change in internal energy

Sign convention for these energies:

For Q: Heat absorbed will be positive and heat released will be negative.

For W: Work done by the system is negative and work done on the system is positive.

For \Delta U: When negative, internal energy is decreasing and when positive, internal energy is increasing.

Hence, the formula used to solve the problems related to first law of thermodynamics is \Delta U=Q+W

8 0
3 years ago
Read 2 more answers
A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

8 0
3 years ago
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