22,200
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The total number of combinations without restrictions is
10 * 10 * 10 * 10 * 10 = 100000
Problem A
10 * 9 * 8 * 7 * 6 = 30240
the number of ways the combination can be set up with no repetition.
The probability of such an event is P = 30240 / 100000 = 0.3024
Problem B
The number of ways that can be done with repetition and no zeros is
9 * 9 * 9 * 9 * 9 = 59049
The probability of such an event is
P = 59049 / 100000 = 0.59049
If the circle has the same center as the diagonals of a square and the radius of the circle is smaller than 1/2 the diagonal of the square but larger than 1/2 the length of the side of a square, then there are 8 points of intersection -- 2 at each corner of the square.
If the radius of the circle is smaller than 1/2 the side length of the square and the center is as described above, there are no points of intersection.
If the circle is located outside the square it can have 1 tangent point or 2 intersection points depending on the location conditions of the circle in relation to the square.
To find out the length of the third segments of the triangle, we can use this formula.
The, third length is very close to the 4. thus, the option (E) is correct.
Answer: On apex it would be answer A the dotted graph with the shaded portion to the bottom left.
Step-by-step explanation:
