First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.
Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.
So x+4 divides 2x^3+2x^2-19x+20.
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
If we factor out a two, we can use the quadratic formula.
2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
The answer is C i’m pretty sure because you can divide y by 15 and get x
92
given 2a² + 5b²
substitute given values for a and b into the expression
2(- 6)² + 5(2)² = (2 × 36 ) + (5 × 4) = 72 + 20 = 92
Answer:
400 sq. ft.
Step-by-step explanation:
We gotta find the length of a side:
First, we divide 80 by 4, because the perimeter of a square is (4 x side):
80 ft. / 4 = 20 ft.
Second, we doing the normal area of a square equation:
= 400 square ft.
Which leads to out answer of 400 sq. ft.
