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3 years ago

Consider the inequality. What is the solution to inequality

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

Answer: $x\leq 2$

Step-by-step explanation:

Paladinen [302]3 years ago

6 0

Answer:

C, hope this helps :)

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What is the prime number 14 13 21 33

kvv77 [185]

Answer:

13 is the prime number

Step-by-step explanation:

Nothing can multiply to produce 13

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3 years ago

PLEASE HELP MEE!!! MAX POINTS AND BRAINLIEST!!

Maurinko [17]

Question does not specify full graph need more information

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3 years ago

So it says change the following fractions and mixed numbers to decimal numbers

puteri [66]

Answer:

2.16666666667 or rounded to 2.17

Step-by-step explanation:

first you have to change the mixed number to an improper fraction which would be 13/6 and then divide the numerator by the denominator

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3 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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3 years ago

Write the expression in standard form: 5(3a) + 8(-5b) + (4 * c * 6) * = Multiplication symbol

scoray [572]

Answer:

use photomath and your welcome :)))

5 0

3 years ago