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Aleks [24]
3 years ago
11

He spent $25 on a box of candy bars and sold them for $2 each. If his profit (after earning back the $25) was $69, how many cand

y bars did Leo sell?
Which equation can be used to solve the problem?


​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

34.50

Step-by-step explanation:

69/2=34.50

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What is the slope of a line that passes through (6,4) and (-1, 3)
pshichka [43]

Answer:

C) 1/7

Step-by-step explanation:

so idk what the formula is called but it looks like this:

y2-y1/x2-x1 and if you plug in the numbers then you'll get the answer

3 - 4/-1 - 6 = -1/-7 = 1/7

you can also switch the numbers your answer will always be the same

4 - 3/6 - (-1) = 1/7

so the answer is c

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3 years ago
3. If RS = 4y -2, ST = 5y -3, and RT = 16y+8. What is the value of y? Find RS, ST, and RT.
kolezko [41]

GOING SEVENTEEN SUPREMACY

5 0
3 years ago
If you can run 3 miles in 20 minutes, how far can you run in one hour?
Irina-Kira [14]

Answer:

I think it would be 9 miles.

3 0
3 years ago
HELP!!! 40 PTS!<br><br> What is its area? Show your work
Vadim26 [7]

a is height p is perimeter

6 0
3 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
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