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3 years ago

Name the property that is illustrated. 1 x 3/4 = 3/4

Mathematics

2 answers:

Tju [1.3M]3 years ago

5 0

Answer:

Associative Property of Addition

ikadub [295]3 years ago

3 0

Identity Property of Multiplication

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Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

Help on how to do this problem

siniylev [52]

Hello!

We can first find RZ. A midpoint is the point right in the middle of a line segment. It splits the line into two equivalent lengths. If z is the midpoint of RT, it therefore splits RT into two equivalent segments, RZ and ZT. Thus, the length of RZ is equivalent to ZT, therefore, the length of RZ is 150.

Next, find RT. We know that RT is made of RZ and ZT, and we know the side lengths of both - 150 and 150. Therefore, add these two together to get the length of RT. 150 + 150 = 300.

Finally, find x. We know that RZ is equal to 150, and we are given 8x - 10 = RZ. Therefore, we know 8x - 10 = 150. Solve this equation for x by isolating x.

8x - 10 = 150

8x = 160

x = 20

Therefore, x = 20.

Your final answer is choice C: x = 20, RZ = 150, and RT = 300.

Hope this helps!

4 0

4 years ago

Read 2 more answers

What is the distance between the points?

Anettt [7]

See the attached picture:

7 0

3 years ago

Freeeeeeeeeeee pointttttttttssss!!!!

Aleks [24]

Answer:

Thank you for the free points

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

you are asked to size the diameter of a bolt loaded in shear to the nearest 1/8 inch with a factor of safety of 1.5. you find th

kupik [55]

Answer:

2.375 inches

Step-by-step explanation:

Main Steps

1. Identifying important parts of the question

2. Solving the problem

Step 1. - Identifying important parts of the question

In the question, there is some extraneous information. For instance, the question introduces the terms "diameter" and "loaded in shear" and "with a safety factor of 1.5". However, given the information in the problem, and the question asked, it isn't necessary to know that it is "loaded in shear" means, or to know what a diameter is (since everything stays with diameters, and doesn't involve another dimension), and the problem gives the result that will satisfy "a safety factor of 1.5".

Sifting through the problem/question, these are the important parts:

- "to the nearest 1/8 inch" (meaning round to the nearest 1/8th of a unit)

- with "units of inches to 3 decimal places"

- The number to round is "2.4183 inches

Step 2. - Solving the Problem

To round to the nearest 1/8 inch, we can divide the number 2.4183 by 1/8.

$2.4183 \div(1/8)$

Recall that dividing by a fraction is the same as multiplying by the reciprocal

$2.4183 * 8$

19.3464

So, there are approximately 19, one-eighth-inches in the measurement. (Note that 19.3464 is closer to 19 than it is to 20). To find the final rounded measurement, multiply 19 by 1/8

$19 * (1/8)$

2.375 inches

So, the diameter of the bolt that should be used (if rounded to the nearest 1/8 inch, to allow for a factor of safety of 1.5) is 2.375 inches

5 0

1 year ago