3 years ago

What is the equation of the line that passes through the point (5,-9) and has a slope of

Mathematics

1 answer:

Helen [10]3 years ago

8 0

Answer:

y=-2/3(x-5)-9

sorry for bad handwriting and forget - with slope

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Sindrei [870]

No solution exists for -3x+y=-18 and -3x+y=-6

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3 years ago

Reduce to the lowest terms 1. 4x^3 y^4 / -8xy^2 2. 3m^2-3n^2 / 6m+6n

lawyer [7]

1.
$\dfrac{4x^{3}y^{4}}{-8xy^{2}}=\dfrac{4}{-8}\cdot x^{3-1}y^{4-2}=\dfrac{-x^{2}y^{2}}{2}$

2.
$\dfrac{3m^{2}-3n^{2}}{6m+6n}=\dfrac{3}{6}\cdot \dfrac{(m+n)(m-n)}{m+n}=\dfrac{m-n}{2}$

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3 years ago

If QR= 3x-2, RS= 2x+1, QS=6x-3, and R is between Q and S, then RS=

rewona [7]

Answer:

RS = 5

Step-by-step explanation:

Since R is between Q and S , then

QS = QR + RS , that is

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6x - 3 = 5x - 1 ( subtract 5x from both sides )

x - 3 = - 1 ( add 3 to both sides )

x = 2

Then

RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5

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3 years ago

(c³d)a(cd⁷)a Simplify

Veseljchak [2.6K]

Answer:

= c^4 d^8 a^2

Step-by-step explanation:

Apply exponent rule: aa= a^2

= c^3 da^2 cd^7

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2 years ago

What is the answer to this

konstantin123 [22]

The answer is 2, the last bubble

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3 years ago

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