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cluponka [151]
2 years ago
5

Which relationship has a zero slope? A two column table with five rows. The first column, x, has the entries, negative 3, negati

ve 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2. A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 3, 1, negative 1, negative 3. A coordinate plane with a straight line starting at (negative 5, negative 5) and passing through the origin, and ending at (5, 5) A coordinate plane with a straight line starting iat (negative 2, 5) and passing the x-axis at (negative 2, 0), and ending at (negative 2, 5).
Mathematics
2 answers:
BigorU [14]2 years ago
7 0

Answer:

y=3 x=1  

Step-by-step explanation:

Softa [21]2 years ago
5 0

Answer:

please add a photo if you have one

Step-by-step explanation:

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Find the value of x, y, and z in the figure below:<br> ہ<br> 2y<br> IN<br> 2x<br> 90°<br> t
natima [27]

Answer:

x=30°

y=15°

z=150°

Step-by-step explanation:

2x+90+x=180°

2x=180°-90°

x=90/3

x=30

2y=x

y= 30/2

y=15°

2y°+z°=180°

2(15°)+z°=180°

z=180°-30°

z=150°

Hope it helps! :)

6 0
2 years ago
PLEASE HELP ASAP 30 POINTS ):
ladessa [460]

Answer:

c (0,-4)

Step-by-step explanation:

-5x+y = -4

4x - 4y =16

Solve the first equation for y since we are using substitution.

-5x+y = -4

Add 5x to each side

-5x+5x+y = -4+5x

y = 5x-4

Substitute this equation y = 5x-4 into the second equation.

4x -4(5x-4) = 16

Distribute the -4

4x - 4(5x) -4(-4) = 16

4x-20x +16 = 16

Combine like terms

-16x +16 =16

Subtract 16 from each side

-16x+16-16 = 16-16

-16x =0

Divide by -16

x=0


But we still need to find y

y = 5x-4

y = 5(0) -4

y = -4

5 0
3 years ago
If two lines intersect at a right angle, then they are perpendicular
kipiarov [429]

This is TRUE!

The definition for perpendicular only applies when the lines are at a right angle which is 90°

4 0
3 years ago
7th grade: CAN SOMEONE PLEASE SOLVE JUST THE TABLES ONLY
Gnom [1K]

Answer:uh

Step-by-step explanation:

8 0
2 years ago
How state the roots as points when I have <br> x=6 and x=-2
dem82 [27]

I don't really know what you're trying to ask because

x = -2 and x=6 are your roots.

But if you want to convert them back to their equation form,

get the other side of the equation to be 0.

x = 6

x - 6 = 0

x = -2

x + 2 = 0

so your original equation had something like (x+2)(x-6)

6 0
3 years ago
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