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Leviafan [203]
3 years ago
10

IS IT CORRECT ?? PLSS

Physics
1 answer:
Pepsi [2]3 years ago
6 0

Answer:

yes it is it looks correct to me

Explanation:

im sorry if it isnt but i just worked out your problem and thats what i had just got

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Teacher ‍ yesss bc i saw
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3 years ago
How does the shape of an plane wing help it to lift off the ground and fly
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8 0
3 years ago
A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat
alexdok [17]

Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

Explanation:

We will use law of conservation of energy to find out the velocity

When the potato is at 2.30 m height, it will have potential energy and when  the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

                       Potential energy = Kinetic energy

                                  m×g×h      = (1/2) m×v²

m stands  for mass

g stands for gravitational constant

h stands for height

v stands for velocity

                      m×g×h      = (1/2) m×v²

                      0.3×9.8×2.3 = (1/2) .3×v²

                       v² = 45.08

                       v  = 6.714 m/s

The speed of the potato at lowest point is 6.714 m/s

Part B

 The potato is in uniform circular motion so the acceleration is given by

                          a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration  is  directly proportional to applied force and inversely proportional to the mass of object

     So                     ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

                     Tension force - Force due to weight = m×a

                     T-m×g     = m×a

           centripetal acceleration formula =v²/r    ,   r = l = length of the string

                        T  = m ×(v²/l) + m×g

  v = 6.714 m/s ,  l = 2.30 m ,   m = .3 kg Now put values in above equation

                         T = .3 × (6.714²/2.30) + .3 × 9.8

                        T  = .3 ( 45.08/2.30) + 2.94

                        T  = .3 (19.6) +2.94

                        T  = 5.88 + 2.94

                        T  = 8.82 N

          The tension in the string is 8.82 N

5 0
3 years ago
What do you notice about where the independent and dependent variables are located on each hypothesis above?!
nata0808 [166]

Answer:

sorry

sorryndd

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8383

48484

8484

4848844

44 the 48844

48484848

4

4 0
3 years ago
A dynamite blast propels a heavy rock straight up with a launch velocity of 160ft/sec (about 109 mph). Write a position for the
Flura [38]
A) Using:
2as = v² - u², where v will be 0 at max height
s = -(160)² / 2 x -32.174
s = 397.8 ft

b) Using:
s = ut + 1/2 at²
256 = 160t - 16.1t²
solving for t,
t = 2.0, t = 7.9
Now, v = u + at, for both times:
v(2) = 160 - 32.174(2)
v(2) = 95.7 ft/sec on the way up

v(7.9) = 160 - 32.174(7.9)
v(7.9) = -94.3 ft/sec; 94.3 ft/sec on the way down

c) -32.174 ft/s², which is the acceleration due to gravity.

d) s = 0
0 = 160t - 1/2 x 32.174t²
t = 9.94 seconds
3 0
4 years ago
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