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gregori [183]
4 years ago
10

A proton beam in an accelerator carries a current of 134 µa. if the beam is incident on a target, how many protons strike the ta

rget in a period of 16.0 s?
Physics
1 answer:
forsale [732]4 years ago
6 0
The intensity of current is defined as the quantity of charge Q that passes through a certain point in a time \Delta t:
I= \frac{Q}{\Delta t}

In our problem, the current is 
I=134 \mu A= 134 \cdot 10^{-6}A while the time interval is 16.0 s, so we can use the previous equation to find the total charge that strikes the target in this time:
Q=I \Delta t=(134 \cdot 10^{-6}A)(16.0 s)=2.1 \cdot 10^{-3}C

We know that each proton carries a charge of q=1.6 \cdot 10^{-19}C, so we can find the number of protons that strike the target by dividing the total charge by the charge of a single proton:
N= \frac{Q}{q}= \frac{2.1 \cdot 10^{-3} C}{1.6 \cdot 10^{-19}C}=1.3 \cdot 10^{16}
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A gas cylinder is filled with 4.00 moles of oxygen gas at 300.0 k. the piston is compressed to yield a pressure of 400.0 kpa. wh
Radda [10]
To answer this item, it is assumed that the gas in the cylinder is ideal such that it follows the equation,
                                        PV = nRT
when V is to be calculated,
                                              V = nRT/P
        V = (4)(0.0821 L.atm/molK)(300 K) / (400 kPa/101.325 kPa/atm)  
                                                V = 24.95 L
Thus, the volume of gas in the cylinder is 24.95 L. 
8 0
3 years ago
Whenever energy changes form, people sometimes say that some energy is "lost." What is meant by this?
BartSMP [9]

Answer:

A. The energy is not truly lost: it transforms into forms that are not easily put to use.

Explanation:

This is due to the fact that when we use energy, it seems to have disappear, but it really hasn't. In fact, when we use energy, it is changing into another form that has to be converted in order for energy to be present once again.

7 0
3 years ago
A barrel 1 m tall and 60 cm in diameter is filled to the top with water. What is the pressure it exerts on the floor beneath it?
allsm [11]

Answer:

The pressure on the ground is about 9779.5 Pascal.

The pressure can be reduced by distributing the weight over a larger area using, for example, a thin plate with an area larger than the circular area of the barrel's bottom side.  See more details further below.

Explanation:

Start with the formula for pressure

(pressure P) = (Force F) / (Area A)

In order to determine the pressure the barrel exerts on the floor area, we need the calculate the its weight first

F_g = m \cdot g

where m is the mass of the barrel and g the gravitational acceleration. We can estimate this mass using the volume of a cylinder with radius 30 cm and height 1m, the density of the water, and the assumption that the container mass is negligible:

V = h\pi r^2=1m \cdot \pi\cdot 0.3^2 m^2\approx 0.283m^3

The density of water is 997 kg/m^3, so the mass of the barrel is:

m = V\cdot \rho = 0.283 m^3 \cdot 997 \frac{kg}{m^3}= 282.151kg

and so the weight is

F_g = 282.151kg\cdot 9.8\frac{m}{s^2}=2765.08N

and so the pressure is

P = \frac{F}{A} = \frac{F}{\pi r^2}= \frac{2765.08N}{\pi \cdot 0.3^2 m^2}\approx 9779.5 Pa

This answers the first part of the question.

The second part of the question asks for ways to reduce the above pressure without changing the amount of water. Since the pressure is directly proportional to the weight (determined by the water) and indirectly proportional to the area, changing the area offers itself here. Specifically, we could insert a thin plate (of negligible additional weight) to spread the weight of the barrel over a larger area. Alternatively, the barrel could be reshaped (if this is allowed) into one with a larger diameter (and smaller height), which would achieve a reduction of the pressure.  

7 0
3 years ago
A uniform disk has a mass of 3.7 kg and a radius of 0.40 m. The disk is mounted on frictionless bearings and is used as a turnta
nevsk [136]

Answer:

1.25 kgm²/sec

Explanation:

Disk inertia, Jd =

Jd = 1/2 * 3.7 * 0.40² = 0.2960 kgm²

Disk angular speed =

ωd = 0.1047 * 30 = 3.1416 rad/sec

Hollow cylinder inertia =

Jc = 3.7 * 0.40² = 0.592 kgm²

Initial Kinetic Energy of the disk

Ekd = 1/2 * Jd * ωd²

Ekd = 0.148 * 9.87

Ekd = 1.4607 joule

Ekd = (Jc + 1/2*Jd) * ω²

Final angular speed =

ω² = Ekd/(Jc+1/2*Jd)

ω² = 1.4607/(0.592+0.148)

ω² = 1.4607/0.74

ω² = 1.974

ω = √1.974

ω = 1.405 rad/sec

Final angular momentum =

L = (Jd+Jc) * ω

L = 0.888 * 1.405

L = 1.25 kgm²/sec

4 0
4 years ago
How do I do balance equations?
san4es73 [151]

Answer:

1. Count the atoms of each element in the reactants and the products.

2. Use coefficients; place them in front of the compounds as needed.

Explanation:

4 0
3 years ago
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