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shtirl [24]
3 years ago
10

the respiratory system includes a layer of cells in the air passage that clean the air before it gets to the lungs.this layer of

cells if best classified as
Chemistry
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

This layer of cells is best classified as a tissue.

Explanation:

When a group of cells comes together to perform a specific function, they are called tissues. It's when a group of tissues comes together to perform a specified function that they become an organ.

You might be interested in
Why is O2 necessary for rusting?
Charra [1.4K]

O2 isn't necessary for rusting, but some source of oxygen is required. Rust is just another name for iron oxide, and without oxygen there can't be oxide.

Hope this helps,

Davinia.

5 0
3 years ago
Read 2 more answers
How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th
OLEGan [10]

Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

<em>How much heat energy is required to convert 48.3 g of solid ethanol at -114.5°C to gaseous ethanol at 135.3 °C?</em>

<em />

We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

48.3g.\frac{1mol}{46.07g} =1.05mol

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

3 0
3 years ago
Aqueous acetic acid is neutralized by aqueous barium hydroxide. express your answer as a balanced molecular equation. identify a
Studentka2010 [4]

The balanced molecular equation for the given reaction is:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<h3>FURTHER EXPLANATION</h3>

To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<u>Reactants </u>                  →                 <u>Products</u>

C:  (2 x 2) =4                                  C: (2 x 2) = 4

H: (2 x 4) + (1 x 2) =10                    H: (3 x 2) + (2 X 2) = 10

O: (2 x 2) + (1 x 2) = 6                    O: (2 x 2) + (2 x 1) = 6

Ba: 1                                               Ba: 1

Since the number of atoms of each element are similar in the reactants and products, the equation is balanced.

To determine the state of the substances, consider their solubility.

The reactants are both aqueous (aq) as indicated in the problem.

The first product, Ba(CH_3COO)_2 is aqueous (aq) because based on the solubility rule, it will dissolve in water. Acetates are generally soluble.

The other product is water which will be liquid (l) since it is the solvent used to dissolve the substances.

<h3>LEARN MORE</h3>
  • Solubility Rules brainly.com/question/12984314
  • Net Ionic Equation brainly.com/question/12980075

Keywords: acid-base, neutralization, balancing equations, molecular equation

7 0
3 years ago
Read 2 more answers
Find the volume of hydrogen gas formed when 1.5g of aluminum reacts with aq NaOH at 27 degrees Celcius.
Rudiy27

Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

8 0
2 years ago
Sodium sulphate reacts with calcium nitrate to produce sodium nitrate and calcium sulphate. A) identify the reactants and produc
Rudik [331]

Answer:

yes ...................

6 0
3 years ago
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