Answer:
a) 6 mol H2O
b) this reaction is endothermic
c) when 1 mol of CO2 is used, in the reaction they occur 0.5025 KJ
Explanation:
balanced eq:
- 6CO2 + 6H2O + 2678 KJ ↔ C6H12O6 + 6O2
6 - C - 6
18 - O - 18
12 - H - 12
a) mol H2O = 6 mol.......from balanced equation.
b) ΔE = 2678 KJ....... this reaction absorbs heat ( ΔE is positive )
c) 1 gramo C6H12O6 ≅ 4 cal
- Mw C6H12O6 = 180.156 g/mol
⇒ 1mol CO2 * ( mol C6H12O6 / 6mol CO2 ) =0.166 mol C6H12O6
⇒ 0.166mol C6H12O6 * ( 180.156 g C6H12O6 / mol ) = 30.026g C6H12O6
⇒30.026 gC6H12O6 * ( 4 cal / gC6H12O6 ) * ( Kcal / 1000 cal ) * (4184 J / Kcal ) * ( KJ / 1000 J ) = 0.5025 KJ C6H12O6.
The question is incomplete, the complete question is
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V
Answer:
only IV and V
Explanation:
If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.
On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.
This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.
The correct answer is D<span>) remains hazardous for a long time. Nuclear waste stays radioactive for many centuries.
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This is generally buried underground, so it does not cause significant air pollution, greenhouse effect, or acid rain<span>. These three are mostly caused by particulate matter or greenhouse gases that are emitted into the atmosphere
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