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ArbitrLikvidat [17]
3 years ago
7

A gas exerts a pressure of 350.0 torr at 20.0 Celsius. What would be the new pressure in atmospheres if the temperature is raise

d to 40.0 Celsius
Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

0.49 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Initial pressure = 350.0 torr

Initial temperature (T1) = 20°C

Final temperature (T2) = 40°C

Final pressure (P2) =?

Step 2:

Conversion to appropriate unit.

It is so vital to convert the units of the variable given to the appropriate unit in order to obtain the desired answer in the right unit. This is illustrated below:

For pressure:

760 torr = 1 atm

Therefore, 350 torr = 350/760 = 0.46 atm

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

T1 = 20°C = 20°C + 273 = 293K

T2 = 40°C = 40°C + 273 = 313K

Step 3:

Determination of the new pressure.

The new pressure can be obtained by applying the following equation:

P1/T1 = P2/T2

P = 0.46 atm

T1 = 293K

T2 = 313K

P2 =?

P1/T1 = P2/T2

0.46 / 293 = P2 / 313

Cross multiply to express in linear form

293 x P2 = 0.46 x 313

Divide both side by 293

P2 = (0.46 x 313) /293

P2 = 0.49 atm

Therefore, the new pressure is 0.49 atm

IgorC [24]3 years ago
5 0

Answer:

373.88 torr

Explanation:

P1 = 350 torr

T1 = 20°C = (20 + 273.15)K = 293.15K

P2 = ?

T2 = 40°C = (40 + 273.15)K = 313.15K

From pressure law,

Pressure of a given mass of gas is directly proportional to its temperature.

P = KT

K = P / T

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 * T2) / T1

P2 = (350 * 313.15) / 293.15

P2 = 109602.5 / 293.15

P2 = 373.878 torr

P2 = 373.88 torr

The new pressure of the gas would be 373.88 torr.

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Answer :

As we know that there are two types of solids.

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Amorphous Solids : It is a type of solids in which the constituent particles of the matter are arranged in the random manner.

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The examples of amorphous solid are, plastics, glass, rubber, metallic glass, polymers, gel, fused silica, pitch tar, thin film lubricants, wax.

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You place 12.0 milliliters of water in a graduated cylinder. Then you add 15.0 grams of metal to the water and the new water lev
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Answer:

<h3>The answer is 7.85 g/mL</h3>

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Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
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Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

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Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

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Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

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\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

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