The reaction is not balanced
<h3>Further explanation</h3>
Given
Reaction
2Fe(s)+3O₂(g)⇒2Fe₂O₃(s)
Required
The number of atoms
Solution
In a balanced chemical equation, the number of atoms in the compound that reacts (the reactants and products) will have the same number
Reactants : Fe(s)+O₂(g)
Fe = 2 atoms
O = 3 x 2 = 6 atoms
Products : Fe₂O₃(s)
Fe = 2 x 2 = 4 atoms
O = 2 x 3 = 6 atoms
The reaction is not balanced because the number of Fe atoms is not the same
The balanced reaction should be:
4Fe(s)+3O₂(g)⇒2Fe₂O₃(s)
Answer:
a. 174 mL
Explanation:
Let's consider the following reaction.
2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)
We have 155.0 mL of a 0.112 M lead(II) nitrate solution. The moles of Pb(NO₃)₂ are:
0.1550 L × 0.112 mol/L = 0.0174 mol
The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:
2 × 0.0174 mol = 0.0348 mol
The volume of a 0.200 M KI solution that contains 0.0348 moles is:
0.0348 mol × (1 L / 0.200 mol) = 0.174 L = 174 mL
Answer:
34.02 g.
Explanation:
Hello!
In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

So probably, the gas may be H₂S.
Best regards!
Answer:
Por favor,no ponga exactamente lo que pongo,Trate de parafrasear.
La espectroscopia es el estudio de la interacción entre la materia y la radiación electromagnética en función de la longitud de onda o frecuencia de la radiación. La espectroscopia puede ser muy útil para ayudar a los científicos a comprender cómo un objeto como un agujero negro, una estrella de neutrones o una galaxia activa produce luz, qué tan rápido se mueve y de qué elementos está compuesto. Se pueden producir espectros para cualquier energía de la luz, desde ondas de radio de baja energía hasta rayos gamma de muy alta energía.
Responde a esta pregunta?
Answer,
For example, silver ion can be precipitated with hydrochloric acid to yield solid silver chloride. Because many cations will not react with hydrochloric acid in this way, this simple reaction can be used to separate ions that form insoluble chlorides from those that do not.