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A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the

WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

$m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\$

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

$(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\$

v_f = 10.85 m/s

8 0

3 years ago

hich answer represents a speed, not a velocity? A. 35 m/s east B. –35 m/s down C. 35 m/s D. 35 m/s south

finlep [7]

The answer is C. 35m/s because there is no direction

3 0

3 years ago

Read 2 more answers

What is the pressure level on surface of titan?

Tcecarenko [31]

150 kPa
While Titan is Saturns largest moon, it only has a mass of 0.0225 Earths

4 0

3 years ago

A motorboat accelerates uniformly from a velocity of 6.5 m/s west to a velocity of 1.5 m/s west. If its acceleration was 2.7 m/s

expeople1 [14]

Answer:

The motorboat ends up 7.41 meters to the west of the initial position

Explanation:

Accelerated Motion

The accelerated motion describes a situation where an object changes its velocity over time. If the acceleration is constant, then these formulas apply:

$\vec v_f=\vec v_o+\vec a.t$

$\displaystyle \vec r=\vec v_o.t+\frac{\vec a.t^2}{2}$

The problem provides the conditions of the motorboat's motion. The initial velocity is 6.5 m/s west. The final velocity is 1.5 m/s west, and the acceleration is $2.7 m/s^2$ to the east. Since all the movement takes place in one dimension, we can ignore the vectorial notation and work with the signs of the variables, according to a defined positive direction. We'll follow the rule that all the directional magnitudes are positive to the east and negative to the west. Rewriting the formulas:

$v_f=v_o+a.t$

$\displaystyle x=v_o.t+\frac{a.t^2}{2}$

Solving the first one for t

$\displaystyle t=\frac{v_f-v_o}{a}$

We have

$v_o=-6.5,\ v_f=-1.5,\ a=2.7$

Using these values

$\displaystyle t=\frac{-1.5+6.5}{2.7}=1.852\ s$

We now compute x

$\displaystyle x=(-6.5)(1.852)+\frac{(2.7)(1.852)^2}{2}$

$x=-7,41\ m$

The motorboat ends up 7.41 meters to the west of the initial position

5 0

3 years ago

Which answer shows a balanced nuclear equation for the alpha decay of plutonium-239

Sergio [31]

Answer: An alpha particle is a helium-4 nucleus, it contains gwo protons and two neutrons. So, alpha decay, giving off an alpha particle, does the following:

1)reduces the atomic number (number of just protons) by two. Plutonium has atomic number of 94, take two protons away and you are left with 92 which corresponds to uranium.

2) reduces the mass number (protons plus neutrons) by 4. If you start with 239 and subtract two protons and two neutrons, you are left with 235.

Explanation:

7 0

3 years ago