The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,
:
First we need to find the net charge flowing at a certain point of the wire in one second,
. Using I=0.92 A and re-arranging the previous equation, we find
Now we know that each electron carries a charge of
, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
Answer:
Jupiter
Explanation:
For this space trip, the distance to the planet must be taken into account, so Because Jupiter is much closer it should be the correct choice
.
It must also be taken into account that Saturn has a series of rings, for which the ship has a probability of colliding with one of these in one of its turns, therefore taking this into account, Jupiter must also be chosen.
The periodic table is arranged in a way that trends are present in columns and rows. Elements belonging to the same column belongs to the same family which means they have the same properties. Elements belonging to the same row have the same number of electron shells. Example of elements with the same chemical properties are Na, Li, and K all belonging to the same group.
So the equation used in this problem is ΔX=V0*T+1/2AT^2 the X is the distance, v0 is initial velocity, T is time, and a is acceleration. So when we plug these values it we get: 108= 0•T+1/2•3•T^2,the 0•t disappears, and the 1/2•3 gets us 1.5, so we have 108=1.5T^2, then we divide 108 by 1.5 which gets us 72=t^2, and we then take the square root and get 8.49=T so the answer is 8.49 seconds.
