Find Lim f(x) as x->0
for
f(x)=5x-8 ......x<0
f(x)=|-4-x|......x ≥ 0
Clearly
f(0)=|-4-0|=|-4|=4 exists.
The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8
The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4
Since the left and right limits do not both equal f(0), the limit does not exist.
.03*.03=.009 .009*.03=.000027 so the answer is .000027
Your answer would be
8y^7
-------
3X^3
√300 = √100.√3 = 10.√3 and √3 is approx 1.732 therefore 10*1.732= 17.32.
therefore the integers it's between are 16 and 17